Thursday, November 19, 2009

Thinking Mathematically Problem Solving

It was a fun to solve this problem bcs it was like a game of numbers to win. The problem is to check a number best to start when playing in pair of two . The numbers given are 1,2,34,5
the players alternately name a number .The winner will be that person who first brings a combined total of 31.
2.Can you find a strategy.
3. what if 31 changes to another number.
4. What if numbers are 1,3,5 or 2,3,7.


I figured out total of digits 1,2,3,4,5 is 15 so I thought 15+15=30.i.e two full rounds of all digits and 30+1 is the game to win.In other words if I start announcing 1 as a first number then a total of 31 can be achieved at the end with 1.
Again if total changes to 33 then I can start with 2 and so on for 35 or 37 .........also for 29, 27.............. At the same time if digits change to 1,3,5 I was able to follow the same strategy of starting with 1 for a total of 31.Bcs every time it follows a sequence of choosing number from a fixed group of numbers. So it looks to me as a fixation of numbers.I found it is the best strategy only if the players have to select all digits differently in all rounds.If all digits can be repeated the I can go simply choosing 24+7, 26+5, 25+6 or 28+3 and so on..................... but then second player can also choose the last number to announce by figuring out the total before the last number.

1 comment:

  1. what a great way of thinking of this problem! It was neat how you added the numbers up to get 15 and then came to the solution that if each of those numbers was used twice starting with 1 is the best way to go!

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